SOAL :
Selesaikan
Tabel simpleks berikut hingga mencapai nilai optimal!
Cj
|
80
|
100
|
0
|
0
|
0
|
||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
|
S1
|
18
|
||||||
S2
|
20
|
||||||
S3
|
4
|
||||||
Zj
|
|||||||
(Cj-Zj)
|
PENYELESAIAN:
Cj
|
80
|
100
|
0
|
0
|
0
|
||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
|
S1
|
0
|
3
|
2
|
1
|
0
|
0
|
18
|
S2
|
0
|
2
|
4
|
0
|
1
|
0
|
20
|
S3
|
0
|
0
|
1
|
0
|
0
|
0
|
4
|
Zj
|
0
|
0
|
0
|
0
|
0
|
||
(Cj-Zj)
|
80
|
100
|
0
|
0
|
0
|
Pivot = 1
KK = 100
Ratio : Bj/Kolom kunci
18/2 = 9
20/4 = 5
4/1= 4 (BK)
Cj
|
80
|
100
|
0
|
0
|
0
|
||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
|
S1
|
0
|
3
|
0
|
1
|
0
|
0
|
10
|
S2
|
0
|
2
|
0
|
0
|
1
|
0
|
4
|
X2
|
100
|
0
|
1
|
0
|
0
|
0
|
4
|
Zj
|
0
|
100
|
0
|
0
|
0
|
400
|
|
(Cj-Zj)
|
80
|
0
|
0
|
0
|
0
|
Pivot = 2
KK = 80
Ratio :
10/3 = 3,33
4/2 = 2 (BK)
4/0 = tak terhingga
Cj
|
80
|
100
|
0
|
0
|
0
|
||
Basis
|
X1
|
X2
|
S1
|
S2
|
S3
|
bj
|
|
S1
|
0
|
0
|
0
|
1
|
-1,5
|
0
|
4
|
X1
|
80
|
1
|
0
|
0
|
0,5
|
0
|
2
|
X2
|
100
|
0
|
1
|
0
|
0
|
0
|
4
|
Zj
|
80
|
100
|
0
|
40
|
0
|
560
|
|
(Cj-Zj)
|
0
|
0
|
0
|
-40
|
0
|
Karena (Cj-Zj)
< 0 maka didapat nilai optimum sebesar 560
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